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120=6t^2+24t-6
We move all terms to the left:
120-(6t^2+24t-6)=0
We get rid of parentheses
-6t^2-24t+6+120=0
We add all the numbers together, and all the variables
-6t^2-24t+126=0
a = -6; b = -24; c = +126;
Δ = b2-4ac
Δ = -242-4·(-6)·126
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-60}{2*-6}=\frac{-36}{-12} =+3 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+60}{2*-6}=\frac{84}{-12} =-7 $
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